document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=852451>Question 852451</A>: <I><SPAN STYLE=\"word-break: break-all;\"> twice the age of son is 4 years more than the age of his father.findage of son if father is 40 years. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #513362 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=513362\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2S - 4 = F<BR>\n" );
document.write( "F = 40<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Simply substitute the value of F from the second equation into the first.<BR>\n" );
document.write( "2S - 4 = 40<BR>\n" );
document.write( "Add 4 to each side<BR>\n" );
document.write( "2S = 44<BR>\n" );
document.write( "Divide b 2<BR>\n" );
document.write( "S = 22<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Let's prove it.<BR>\n" );
document.write( "Twice the age of the son (22 * 2 = 44) is 4 years older than his father (40).<BR>\n" );
document.write( "44-4=40<BR>\n" );
document.write( "success! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );