document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=852382>Question 852382</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the length of the rectangle is twice the width,and the perimeter of the rectangle is 30cm, what is the length and width of the rectangle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #513358 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=513358\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L = 2W (length of the rectangle is twice the width)<BR>\n" );
document.write( "2L + 2W = 30 (the perimeter of the rectangle is 30cm [perimeter is a fence])<BR>\n" );
document.write( "Substitute the value of L from the first equation into the second<BR>\n" );
document.write( "2(2W) + 2W = 30<BR>\n" );
document.write( "Multiply<BR>\n" );
document.write( "4W + 2W = 30<BR>\n" );
document.write( "Ad<BR>\n" );
document.write( "6W = 30<BR>\n" );
document.write( "Divide each side by 6<BR>\n" );
document.write( "W=5<BR>\n" );
document.write( ".<BR>\n" );
document.write( "If W = 5, then L =10.<BR>\n" );
document.write( "Let's prove it by building a perimeter fence.  We'll need two lengths and two widths.  5 + 5 + 10 + 10 = 30<BR>\n" );
document.write( "Success! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );