document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=852389>Question 852389</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find two consecutive odd integers such that six times the smaller is three more than five times the larger  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #513357 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=513357\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Here's what we know:<BR>\n" );
document.write( "A = B+2 (consecutive odd integers), where B is the smaller number<BR>\n" );
document.write( "6B - 3 = 5A (six times the smaller is three more than five times the larger )<BR>\n" );
document.write( "Substitute the value of A from the first equation into the second.<BR>\n" );
document.write( "6B-3 = 5(B+2)<BR>\n" );
document.write( "Distribute<BR>\n" );
document.write( "6B-3 = 5B+10<BR>\n" );
document.write( "Add 3 to each side<BR>\n" );
document.write( "6B = 5B + 13<BR>\n" );
document.write( "Subtract 5B from each side<BR>\n" );
document.write( "B = 13<BR>\n" );
document.write( ".<BR>\n" );
document.write( "If B is 13, then A is 15.  Let's prove it.<BR>\n" );
document.write( "6*13 = (5*15)+3<BR>\n" );
document.write( "78 = 75+3<BR>\n" );
document.write( "78=78<BR>\n" );
document.write( "Success~! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );