document.write( "Question 852411: The perimeter of a rectangle is 74m. If the width were doubled and the length increased by 10m, the perimeter would be 126m. What are the length and width of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #513334 by josgarithmetic(39630) ![]() You can put this solution on YOUR website! w width, y length\r \n" ); document.write( "\n" ); document.write( "As started: \n" ); document.write( "\n" ); document.write( "As changed: width is 2w, and length is y+10; so perimeter is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Simplifying the two equations, cutting through the steps, the system is: \n" ); document.write( "------------------- \n" ); document.write( "w+y=37 \n" ); document.write( "- \n" ); document.write( "2w+y=53 \n" ); document.write( "-------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Elimination Method: \n" ); document.write( " \n" ); document.write( " |