document.write( "Question 852411: The perimeter of a rectangle is 74m. If the width were doubled and the length increased by 10m, the perimeter would be 126m. What are the length and width of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #513334 by josgarithmetic(39630)\"\" \"About 
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w width, y length\r
\n" ); document.write( "\n" ); document.write( "As started: \"2w%2B2y=74\"\r
\n" ); document.write( "\n" ); document.write( "As changed: width is 2w, and length is y+10; so perimeter is \"2%282w%29%2B2%28y%2B10%29=126\"\r
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\n" ); document.write( "\n" ); document.write( "Simplifying the two equations, cutting through the steps, the system is:
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\n" ); document.write( "w+y=37
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\n" ); document.write( "2w+y=53
\n" ); document.write( "-------------------\r
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\n" ); document.write( "\n" ); document.write( "Elimination Method:
\n" ); document.write( "\"%282w%2By%29-%28w%2By%29=53-37\"
\n" ); document.write( "\"highlight%28w=16%29\", .... \"highlight%28y=21%29\".
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