document.write( "Question 852320: 1 plus the product of 8 and x is equal to y. The product of 12 and x plus the product of 3 and y is 39. Solve the system of equations for x and y using substitution. \n" ); document.write( "
Algebra.Com's Answer #513298 by rvfer(117)\"\" \"About 
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y=8x+1
\n" ); document.write( "12x+3y=39
\n" ); document.write( "--------------
\n" ); document.write( "12x+3(8x+1)=39
\n" ); document.write( "12x+24x+3=39
\n" ); document.write( "36x=39-3
\n" ); document.write( "x=36/36
\n" ); document.write( "x=1
\n" ); document.write( "-----------------
\n" ); document.write( "12*1+3y=39
\n" ); document.write( "3y=39-12
\n" ); document.write( "3y=27
\n" ); document.write( "y=27/3
\n" ); document.write( "y=9
\n" ); document.write( "----
\n" ); document.write( "(1,9)
\n" ); document.write( "------------
\n" ); document.write( "y=8x+1
\n" ); document.write( "9=8*1+1
\n" ); document.write( "9=9
\n" ); document.write( "
\n" );