document.write( "Question 852320: 1 plus the product of 8 and x is equal to y. The product of 12 and x plus the product of 3 and y is 39. Solve the system of equations for x and y using substitution. \n" ); document.write( "
Algebra.Com's Answer #513298 by rvfer(117)![]() ![]() ![]() You can put this solution on YOUR website! y=8x+1 \n" ); document.write( "12x+3y=39 \n" ); document.write( "-------------- \n" ); document.write( "12x+3(8x+1)=39 \n" ); document.write( "12x+24x+3=39 \n" ); document.write( "36x=39-3 \n" ); document.write( "x=36/36 \n" ); document.write( "x=1 \n" ); document.write( "----------------- \n" ); document.write( "12*1+3y=39 \n" ); document.write( "3y=39-12 \n" ); document.write( "3y=27 \n" ); document.write( "y=27/3 \n" ); document.write( "y=9 \n" ); document.write( "---- \n" ); document.write( "(1,9) \n" ); document.write( "------------ \n" ); document.write( "y=8x+1 \n" ); document.write( "9=8*1+1 \n" ); document.write( "9=9 \n" ); document.write( " |