document.write( "Question 852308: What is the solution of the proportion?
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document.write( "n-6= n-5
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document.write( "3n 3n+1\r
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document.write( "I cross multiplied and got (n-6)(3n+1)=3n(n-5) and I then FOILed and did the distributive property and got 3n^2+n-18n-6=3n^2-15n and I am now stuck and have no idea what to do next.. Please Help! Thank You ! :) \n" );
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Algebra.Com's Answer #513292 by josh_jordan(263)![]() ![]() You can put this solution on YOUR website! Hello, I'm unclear as to the actual proportion, but I'm assuming it's\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If this is the case, first, you need to cross-multiply, which you did, and you'd get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(n - 6)(3n + 1) = 3n(n - 5) ----->\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Next, get all of the n's and n^2's to one side, and the numbers to the other side. When you do this, you will get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, you can solve for n, by dividing both sides of the equation by -2:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |