document.write( "Question 852308: What is the solution of the proportion?
\n" ); document.write( "n-6= n-5
\n" ); document.write( "3n 3n+1\r
\n" ); document.write( "\n" ); document.write( "I cross multiplied and got (n-6)(3n+1)=3n(n-5) and I then FOILed and did the distributive property and got 3n^2+n-18n-6=3n^2-15n and I am now stuck and have no idea what to do next.. Please Help! Thank You ! :)
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Algebra.Com's Answer #513292 by josh_jordan(263)\"\" \"About 
You can put this solution on YOUR website!
Hello, I'm unclear as to the actual proportion, but I'm assuming it's\r
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\n" ); document.write( "\n" ); document.write( "\"%28n-6%29%2F3n=%28n-5%29%2F%283n%2B1%29\"\r
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\n" ); document.write( "\n" ); document.write( "If this is the case, first, you need to cross-multiply, which you did, and you'd get:\r
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\n" ); document.write( "\n" ); document.write( "(n - 6)(3n + 1) = 3n(n - 5) ----->\r
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\n" ); document.write( "\n" ); document.write( "\"3n%5E2%2Bn-18n-6=3n%5E2-15n\" ----->\r
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\n" ); document.write( "\n" ); document.write( "\"3n%5E2-17n-6=3n%5E2-15n\"\r
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\n" ); document.write( "\n" ); document.write( "Next, get all of the n's and n^2's to one side, and the numbers to the other side. When you do this, you will get:\r
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\n" ); document.write( "\n" ); document.write( "\"-2n=6\"\r
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\n" ); document.write( "\n" ); document.write( "Now, you can solve for n, by dividing both sides of the equation by -2:\r
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\n" ); document.write( "\n" ); document.write( "\"%28-2n%29%2F-2=6%2F-2\" ----->\r
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\n" ); document.write( "\n" ); document.write( "\"n=-3\", which is your answer
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