document.write( "Question 852054: simplify by using logarithmic law:
\n" ); document.write( "log1 to the base e + 3log10 to the base 10 - log32 to the base 2 \n" ); document.write( "

Algebra.Com's Answer #513280 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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log1 to the base e + 3log10 to the base 10 - log32 to the base 2
\n" ); document.write( " $\"ln%281%29+%2B+3log%2810%29+-+log%282%2C32%29\"$
\n" ); document.write( "the nat log of 1 = 0 so we can ignore that.
\n" ); document.write( " $\"3log%2810%29+-+log%282%2C32%29\"$
\n" ); document.write( " $\"log%2810%5E3%29+-+log%282%2C32%29\"$
\n" ); document.write( " $\"log%281000%29+-+log%282%2C32%29\"$
\n" ); document.write( "we know the log of 1000 is 3
\n" ); document.write( " $\"3+-+log%282%2C32%29\"$
\n" ); document.write( "we know that 32 = 2^5, therefore
\n" ); document.write( "3 - 5 = -2 \n" ); document.write( "

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