document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=852167>Question 852167</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For this function, calculate the equation of the tangent line at the given point\r<BR>\n" );
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document.write( "f(x) = tan x + (x^2/ pie^2) at the point (pie,1)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #513212 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=513212\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For this function, calculate the equation of the tangent line at the given point\r<BR>\n" );
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document.write( "f(x) = tan x + (x^2/ pie^2) at the point (pie,1)<BR>\n" );
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document.write( "I'll use the Greek letter pi, not the dessert, pie.<BR>\n" );
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document.write( "f(x) = tan x + (x^2/ pi^2) at the point (pi,1)<BR>\n" );
document.write( "f'(x) = sec^2(x) + 2x/pi^2<BR>\n" );
document.write( "f'(pi) = 1 + 2pi/pi^2<BR>\n" );
document.write( "= 1 + 2/pi<BR>\n" );
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document.write( "y - 1 = (1 + 2/pi)*(x - pi)<BR>\n" );
document.write( "y = 1 + x - pi + 2x/pi - 2<BR>\n" );
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