document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=852173>Question 852173</A>: <I><SPAN STYLE=\"word-break: break-all;\"> It takes 5 seconds for sound to travel 1 mile through air. It takes only 1 second for sound to travel 1 mile through water. How many minutes faster will a sound 90 miles away travel through water than air?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #513203 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=513203\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It takes 5 seconds for sound to travel 1 mile through air. It takes only 1 second for sound to travel 1 mile through water. How many minutes faster will a sound 90 miles away travel through water than air?<BR>\n" );
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document.write( "\"minutes faster\" makes no sense, minutes is not a unit of speed.<BR>\n" );
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document.write( "To find how many minutes sooner it would arrive, calculate the 2 times.<BR>\n" );
document.write( "d = r*t<BR>\n" );
document.write( "t = d/r<BR>\n" );
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document.write( "In water, r = 1 mi/sec<BR>\n" );
document.write( "In air, r = 1/5 mi/sec\r<BR>\n" );
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document.write( "90 miles in air at 0.2 mi/sec --> 90/0.2 = 450 seconds </SPAN>\n" );
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