document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=71676>Question 71676</A>: <I><SPAN STYLE=\"word-break: break-all;\"> John has 300 feet of lumber to frame a rectangular patio (the perimeter of a rectangle is 2 times length plus 2 times width). He wants to maximize the area of his patio (area of a rectangle is length times width). What should the dimensions of the patio be, and show how the maximum area of the patio is calculated from the algebraic equation.  \r<BR>\n" );
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document.write( "	Show clearly the algebraic steps which prove your dimensions are the maximum area which can be obtained. Use the vertex formula to find the maximum area.\r<BR>\n" );
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document.write( "Answer:	\r<BR>\n" );
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document.write( "Show work in this space. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #51320 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=51320\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THE MAXIMUM AREA OF A RECTANGLE TAKES THE FORM OF A SQUARE. THUS:<BR>\n" );
document.write( "X^2=300<BR>\n" );
document.write( "X=SQRT300<BR>\n" );
document.write( "X=17.32 FEET. ANSWER FOR THE SIDE OF THE SQUARE.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "17.32*17.32=300<BR>\n" );
document.write( "300=300 </SPAN>\n" );
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