document.write( "Question 852149: You want to install a 1 yd wide walk around a circular swimming pool. The diameter of the pool is 24 yds. What is the area of the walk?
\n" ); document.write( "Use 3.14 for pi.
\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #513194 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "The green line is the radius of the swimming pool, the INNER circle.\r\n" );
document.write( "Since its diameter is 24 yards, its radius is 12 yards.\r\n" );
document.write( "Its area is gotten by using A = pr2.\r\n" );
document.write( "A = 3.14×122 = 452.16 square yards.\r\n" );
document.write( "\r\n" );
document.write( "Since the walk around the swimming pool is 1 yd. wide, the radius of\r\n" );
document.write( "the OUTER circle has a radius of 1 yd. more than the radius of the inner \r\n" );
document.write( "circle, or 13 yd. Its area is also gotten by using A = pr2.\r\n" );
document.write( "A = 3.14×132 = 530.66 square yards.\r\n" );
document.write( "\r\n" );
document.write( "Area of walk = Area of OUTER circle MINUS Area of INNER circle:\r\n" );
document.write( "\r\n" );
document.write( "Answer: 530.66 sq. yd. - 452.16 = 78.5 square yards. \r\n" );
document.write( "\r\n" );
document.write( "Edwin

\n" ); document.write( " \n" ); document.write( "
\n" );