document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=852078>Question 852078</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A regular hexagon with a side length of 4 has the same area of a square. What is the length of the side of the square? Explain how you know. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #513175 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=513175\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The area of a regular polygon is<BR>\n" );
document.write( "A = (S^2 * N) / 4tan(180/N), where S is length of side and N is number of sides<BR>\n" );
document.write( "now for our hexagon of side length 4 and 6 sides we have<BR>\n" );
document.write( "A = (4^2 * 6) / 4tan(180/6) = 96 / 2.31 = 41.6<BR>\n" );
document.write( "now the area of a square is S^2, where S is the length of a side<BR>\n" );
document.write( "A = 41.6 = S^2<BR>\n" );
document.write( "S = square root of 41.6<BR>\n" );
document.write( "S = 6.4<BR>\n" );
document.write( "length of the side of the square is 6.4<BR>\n" );
document.write( " </SPAN>\n" );
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