document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=852119>Question 852119</A>: <I><SPAN STYLE=\"word-break: break-all;\"> binomial distribution \r<BR>\n" );
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document.write( "A quality inspector has drawn a sample of 16 light bulbs from a recent production line. Supposed 20% of the bulbs in the lot are defective. What is the probability that exactly 6 bulbs from the sample are defective?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #513165 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=513165\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We are going to use the General Binomial Probability formula<BR>\n" );
document.write( "P(k out of n) = n!/(k!(n-k)!) * p^k * (1-p)^(n-k)<BR>\n" );
document.write( "p = .20<BR>\n" );
document.write( "k = 6<BR>\n" );
document.write( "n = 16<BR>\n" );
document.write( "P(6 out of 16) = 16! /(6!(16-6)!) * .2^6 * (1-.2)^(16-6)<BR>\n" );
document.write( "P(6 out of 16) =  8008 * 6.4e-5 * 0.1073741824<BR>\n" );
document.write( "P(6 out of 16) = 0.0550 = 0.06<BR>\n" );
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