document.write( "Question 852124: If the probability of a tennis player serving an ace is 1/6, what's the probability that the player will serve 3 aces out of 8 serves?\r
\n" ); document.write( "\n" ); document.write( "I know it's independent probability. I did it like this:
\n" ); document.write( "for \"non-ace\" results, the prob. is 5/6
\n" ); document.write( "for 8 serves, the prob of 3 aces is:\r
\n" ); document.write( "\n" ); document.write( "1/6 * 1/6 * 1/6 * 5/6 * 5/6 * 5/6 * 5/6 * 5/6 = 3125/1,679,616 = approx. 0.00186, or 0.186%, or 186/1000.\r
\n" ); document.write( "\n" ); document.write( "Am I even close?
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Algebra.Com's Answer #513164 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
 
\n" ); document.write( "Hi,
\n" ); document.write( "Note: The probability of x successes in n trials is:
\n" ); document.write( "P (x)= \"nCx+%28p%5Ex%29%28q%29%5E%28n-x%29\" where p and q are the probabilities of success and failure respectively.
\n" ); document.write( "In this case p = 1/6 & q = 5/6 n = 8
\n" ); document.write( " = \"%28n%21%29%2Fx%21%28n+-+x%29%21+=+8%2A7%2A6%2F%282%2A3%29+=+56\"
\n" ); document.write( "P(x=3) =\"+56%281%2F6%29%5E3%285%2F6%29%5E5+=+.1042\" You had just not used the 'combination factor' of 56
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