document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=852053>Question 852053</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "if two complementary angles differ by 20 degree,find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #513160 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=513160\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X+Y=90 DEGREES.<BR>\n" );
document.write( "X=Y+20<BR>\n" );
document.write( "(Y+20)+Y=90<BR>\n" );
document.write( "2Y=90-20<BR>\n" );
document.write( "2Y=70<BR>\n" );
document.write( "Y=70/2<BR>\n" );
document.write( "Y=35 DEGREES FOR THE SMALLER ANGLE<BR>\n" );
document.write( "X=35+20=55 DEGREES FOR THE LARGER ANGLE.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "35+55=90<BR>\n" );
document.write( "90=90 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );