document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=851947>Question 851947</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log3(x+3)=2+log3(x-1)             [3's are the bases]\r<BR>\n" );
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document.write( "I have:<BR>\n" );
document.write( "log3(x+3)-log3(x-1)=2<BR>\n" );
document.write( "log3[(x+3)/(x-1)]=2<BR>\n" );
document.write( "3^2=(x+3)/(x-1)<BR>\n" );
document.write( "9x-9=x+3<BR>\n" );
document.write( "8x=12<BR>\n" );
document.write( "x=2/3\r<BR>\n" );
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document.write( "The answer is supposedly 1.5, but I am getting 2/3.. help?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #513033 by </B><A HREF=/tutors/aboutme.mpl?userid=josh_jordan><B>josh_jordan(263)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josh_jordan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=josh_jordan><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=513033\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You were correct up until 8x = 12.\r<BR>\n" );
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document.write( "When you divide both sides of your equation by 8, you get \r<BR>\n" );
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document.write( "x = 12/8, which equals 3/2, not 2/3.  3/2 = 1.5  :) </SPAN>\n" );
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