document.write( "Question 851772: Solve the inequality 2x - 3 < x + 2 ≤ 3x + 5\r
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document.write( "You dont need to graph it I just need help solving it, thanks \n" );
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Algebra.Com's Answer #513004 by josh_jordan(263)![]() ![]() You can put this solution on YOUR website! Hello,\r \n" ); document.write( "\n" ); document.write( "2x - 3 < x + 2 ≤ 3x + 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1. Separate these into two different inequalities:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x - 3 < x + 2 AND x + 2 ≤ 3x + 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2. Solve for x in each inequality:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x - 3 < x + 2 -----> x < 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + 2 ≤ 3x + 5 -----> -3 ≤ 2x -----> -3/2 ≤ x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We now know that x must be less than 5 and greater than -3/2. So, \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-3/2 ≤ x < 5 which is your final answer. \n" ); document.write( " |