document.write( "Question 851772: Solve the inequality 2x - 3 < x + 2 ≤ 3x + 5\r
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Algebra.Com's Answer #513004 by josh_jordan(263)\"\" \"About 
You can put this solution on YOUR website!
Hello,\r
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\n" ); document.write( "\n" ); document.write( "1. Separate these into two different inequalities:\r
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\n" ); document.write( "\n" ); document.write( "2x - 3 < x + 2 AND x + 2 ≤ 3x + 5\r
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\n" ); document.write( "\n" ); document.write( "2. Solve for x in each inequality:\r
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\n" ); document.write( "\n" ); document.write( "2x - 3 < x + 2 -----> x < 5\r
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\n" ); document.write( "\n" ); document.write( "x + 2 ≤ 3x + 5 -----> -3 ≤ 2x -----> -3/2 ≤ x\r
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\n" ); document.write( "\n" ); document.write( "We now know that x must be less than 5 and greater than -3/2. So, \r
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\n" ); document.write( "\n" ); document.write( "-3/2 ≤ x < 5 which is your final answer.
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