document.write( "Question 851788: A boat travels 15km/hr in still water. In travelling 45 km downstream from Town A to Town B, it completes the journey in 75 minutes less than it takes for the return journey. At what speed does the river flow?
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document.write( "Please explain simply. Apparently I am an idiot. \n" );
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Algebra.Com's Answer #512999 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! A boat travels 15km/hr in still water. In travelling 45 km downstream from Town A to Town B, it completes the journey in 75 minutes less than it takes for the return journey. At what speed does the river flow? \n" ); document.write( "*** \n" ); document.write( "let x=speed of river flow \n" ); document.write( "15+x=speed of boat downstream \n" ); document.write( "15-x=speed of boat upstream \n" ); document.write( "travel time=distance/speed \n" ); document.write( "... \n" ); document.write( "travel time upstream=45/(15-x) (return trip) \n" ); document.write( "travel time downstream=45/(15+x) \n" ); document.write( "75 min=(75/60) hr \n" ); document.write( " \n" ); document.write( "LCD:(15-x)(15+x)(60) \n" ); document.write( " \n" ); document.write( "40500+2700x-40500+2700x=75(225-x^2) \n" ); document.write( "5400x=16875-75x^2 \n" ); document.write( "75x^2+5400x-16875=0 \n" ); document.write( "divide by 75 \n" ); document.write( "x^2+72-225=0 \n" ); document.write( "solve for x by quadratic formula: \n" ); document.write( " \n" ); document.write( "a=1, b=72, c=-225 \n" ); document.write( "ans: \n" ); document.write( "x=-12.37 (reject) \n" ); document.write( "or \n" ); document.write( "x=12.37 \n" ); document.write( "speed of river flow=12.37 km/hr\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |