document.write( "Question 851722: Algebra 2 question! Help me please! I have a test on this stuff later today and I am very confused. Please just show all of your steps and explain in detail thanks!\r
\n" ); document.write( "\n" ); document.write( "Consider the infinite geometric series :
\n" ); document.write( "infinity
\n" ); document.write( " E -4(1/3)^n-1
\n" ); document.write( " n=1
\n" ); document.write( "Write the first four terms of the series.
\n" ); document.write( "Does the series diverge or converge?
\n" ); document.write( "If the series has a sum, find the sum.\r
\n" ); document.write( "\n" ); document.write( "Thank you!! \n" ); document.write( "

Algebra.Com's Answer #512964 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"Sum=sum%28-4%281%2F3%29%5E%28n-1%29%2Cn=1%2Cinfinity%29\"$
\n" ); document.write( " $\"n=1\"$ , $\"-4%281%2F3%29%5E%281-1%29=-4%281%2F3%29%5E0=-4\"$
\n" ); document.write( " $\"n=2\"$ , $\"-4%281%2F3%29%5E%282-1%29=-4%281%2F3%29%5E1=-4%2F3\"$
\n" ); document.write( " $\"n=3\"$ , $\"-4%281%2F3%29%5E%283-1%29=-4%281%2F3%29%5E2=-4%2F9\"$
\n" ); document.write( " $\"n=4\"$ , $\"-4%281%2F3%29%5E%284-1%29=-4%281%2F3%29%5E3=-4%2F27\"$
\n" ); document.write( "Converges since $\"abs%281%2F3%29%3C1\"$
\n" ); document.write( " $\"Sum=-4%281%2F%281-1%2F3%29%29=-4%281%2F%282%2F3%29%29=-4%283%2F2%29=-6\"$ \n" ); document.write( "

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