document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=851698>Question 851698</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if sinx= 3/5 on the interval(pi/2,pi), find the eact value of tan2x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #512938 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=512938\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if sinx= 3/5 on the interval(pi/2,pi), find the exact value of tan(2x)<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "tan(2x) = [2tan(x)]/[1-tan^2(x)]<BR>\n" );
document.write( "------<BR>\n" );
document.write( "Since sin(x) = 3/5, cos(x) = sqrt(5^2-3^2)/5 = sqrt(16)/5 = 4/5<BR>\n" );
document.write( "Then tan(x) = sin(x)/cos(x) = 4/3<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Therefore: tan(2x) = [2(4/3)]/(1-(4/3)^2] = (8/3)/(-7/9) = -16/7<BR>\n" );
document.write( "==================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "================== </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );