document.write( "Question 851668: I have before me three numeric palindromes (numbers which read the same backwards and forwards, like 838). The first number is two digits long; the second is three digits, and when we add those two numbers together we get the third number, which is four digits long. What are the three numbers? \n" ); document.write( "
Algebra.Com's Answer #512924 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! the third must end in 1 \n" ); document.write( "1xx1 \n" ); document.write( "first must be one of these \n" ); document.write( "11,22,33,44,55,66,77,88,99 \n" ); document.write( "second must be \n" ); document.write( "1y1,2y2,3y3 \n" ); document.write( "4y4,5y5,6y6 \n" ); document.write( "7y7,8y8,9y9\r \n" ); document.write( "\n" ); document.write( "the first and second must add up a number ending in 1 \n" ); document.write( "the first and second must add up a number beginning with 1 \n" ); document.write( "the first and second must add up to a number greater than 1000 \n" ); document.write( "9 and 2 \n" ); document.write( "greater 901 plus 99 is a four digit number \n" ); document.write( "since it begins with 1 it must end in 1\r \n" ); document.write( "\n" ); document.write( "5y5+66 is not 4 digits \n" ); document.write( "so it must 9y9 and 22=1xx1 \n" ); document.write( "909+22+10x=1001+z \n" ); document.write( "931+10a=1001+b, \n" ); document.write( "b=100c+10c \n" ); document.write( "c<10 \n" ); document.write( "a<10 \n" ); document.write( "b>10 \n" ); document.write( "c=0 \n" ); document.write( "999+22=1021 \n" ); document.write( "989+22=1011 \n" ); document.write( "979+22=1001 \n" ); document.write( "bingo\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |