document.write( "Question 851626: a company purchasing department is busy looking at the quality of computers bought by the company. they found that 15% of all new computers screens have to be replaced within 6 months 27% of all new computers must have their screens or mouse replaced within 6 months. given that a computer's mouse was replaced, 10% must also have their screens replaced within 6 months.
\n" ); document.write( "a) what is the probability that a computer's mouse must be replaced within 6 months?
\n" ); document.write( "b) what is the probability that given a computer's screen was replaced, the same computer's mouse will also be replaced within 6 months?
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Algebra.Com's Answer #512914 by stanbon(75887)\"\" \"About 
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a company purchasing department is busy looking at the quality of computers bought by the company.
\n" ); document.write( "they found that 15% of all new computers screens have to be replaced within 6 months P(screens bad) = 0.15
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\n" ); document.write( "27% of all new computers must have their screens or mouse replaced within 6 months. P(screens OR mouse bad) = 0.27
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\n" ); document.write( "given that a computer's mouse was replaced, 10% must also have their screens replaced within 6 months:: P(screens bad | mouse bad) = 0.10
\n" ); document.write( "Note: P(screens AND mouse bad) = 0.10*P(mouse bad)
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\n" ); document.write( "a) what is the probability that a computer's mouse must be replaced within 6 months?
\n" ); document.write( "Note: Since P(A OR B) = P(A)+P(B)-P(A AND B),
\n" ); document.write( "P(m) = P(m OR s)-P(s)+P(m AND s)\r
\n" ); document.write( "\n" ); document.write( "P(mouse bad) = P(screens OR mouse) + P(screens AND mouse)-P(screen)
\n" ); document.write( "P(mouse bad) = 0.27+0.10(mouse bad)-0.15
\n" ); document.write( "0.90P(mouse bad) = 0.12
\n" ); document.write( "P(mouse bad) = 2/15
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\n" ); document.write( "b) what is the probability that given a computer's screen was replaced, the same computer's mouse will also be replaced within 6 months?
\n" ); document.write( "P(mouse bad | screen bad) = P(mouse AND screen bad)/P(screen bad)
\n" ); document.write( "= (0.10)(2/15)/0.15 = 0.089
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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