document.write( "Question 851370: Miguel works three times faster than Steven together they do a job in nine hours How long does it take Steven working alone to do the same job \n" ); document.write( "
Algebra.Com's Answer #512852 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Miguel works three times faster than Steven together they do a job in nine hours How long does it take Steven working alone to do the same job \n" ); document.write( "---------------------- \n" ); document.write( "3 times faster = 4 times as fast \n" ); document.write( "--- \n" ); document.write( "1/M + 1/S = 1/9 \n" ); document.write( "1/4S + 1/S = 1/9 \n" ); document.write( "5/4S = 1/9 \n" ); document.write( "S = 45/4 hours for Steve alone \n" ); document.write( "================================ \n" ); document.write( "3 times faster is an increase of 300% \n" ); document.write( "An increase of 100% is 1 times faster, 2x as fast \n" ); document.write( "An increase of 200% is 2 times faster, 3x as fast \n" ); document.write( "An increase of3100% is 3 times faster, 4x as fast \n" ); document.write( "----- \n" ); document.write( "\"times faster\" is not the same as \"times as fast\" \n" ); document.write( " \n" ); document.write( " |