document.write( "Question 851508: the four numbers are such that the second is 9 less than thrice the first, and the third is six more than the sum of the first two numbers the sum of number is 190 . Find the numbers. \n" ); document.write( "
Algebra.Com's Answer #512836 by JulietG(1812)![]() ![]() You can put this solution on YOUR website! Let the numbers be A, B, C, D \n" ); document.write( "Here's what we are told: \n" ); document.write( "B = 3A-9 (the second is 9 less than thrice the first) \n" ); document.write( "C = A+B+6 (the third is six more than the sum of the first two numbers) \n" ); document.write( "A + B + C + D = 190 (the sum of number is 190) <<--that's an assumption. You didn't use enough punctuation for me to be certain. \n" ); document.write( ". \n" ); document.write( "Substitute the values of B and C into the third equation. \n" ); document.write( "A + (3A-9) + (A+B+6) + D = 190 \n" ); document.write( "Add \n" ); document.write( "5A - 9 + B + 6 + D = 190 \n" ); document.write( "Substitute B again \n" ); document.write( "5A - 9 + (3A-9) + 6 + D = 190 \n" ); document.write( "Add/Subtract \n" ); document.write( "8A -12 + D = 190 \n" ); document.write( "Add 12 to each side \n" ); document.write( "8A + D = 202 \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "You seem to be missing some information in the problem. Would you please check it and resubmit? \n" ); document.write( " |