document.write( "Question 851508: the four numbers are such that the second is 9 less than thrice the first, and the third is six more than the sum of the first two numbers the sum of number is 190 . Find the numbers. \n" ); document.write( "
Algebra.Com's Answer #512836 by JulietG(1812)\"\" \"About 
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Let the numbers be A, B, C, D
\n" ); document.write( "Here's what we are told:
\n" ); document.write( "B = 3A-9 (the second is 9 less than thrice the first)
\n" ); document.write( "C = A+B+6 (the third is six more than the sum of the first two numbers)
\n" ); document.write( "A + B + C + D = 190 (the sum of number is 190) <<--that's an assumption. You didn't use enough punctuation for me to be certain.
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\n" ); document.write( "Substitute the values of B and C into the third equation.
\n" ); document.write( "A + (3A-9) + (A+B+6) + D = 190
\n" ); document.write( "Add
\n" ); document.write( "5A - 9 + B + 6 + D = 190
\n" ); document.write( "Substitute B again
\n" ); document.write( "5A - 9 + (3A-9) + 6 + D = 190
\n" ); document.write( "Add/Subtract
\n" ); document.write( "8A -12 + D = 190
\n" ); document.write( "Add 12 to each side
\n" ); document.write( "8A + D = 202
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\n" ); document.write( "You seem to be missing some information in the problem. Would you please check it and resubmit?
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