document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=851512>Question 851512</A>: <I><SPAN STYLE=\"word-break: break-all;\"> sqrt-5a+6 = -a<BR>\n" );
document.write( "(-5a+6 are all under the same square root sign)\r<BR>\n" );
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document.write( "I'm not asking for someone to give me the answer. I just need help with all the steps, if you would like to give the answer, that would still be appreciated, but not a complete necessity. Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #512811 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=512811\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sqrt(-5a+6) = -a<BR>\n" );
document.write( "square both sides to get:<BR>\n" );
document.write( "-5a+6 = (-a)^2<BR>\n" );
document.write( "since (-a)^2 is equal to a^2, your equation becomes:<BR>\n" );
document.write( "-5a+6 = a^2<BR>\n" );
document.write( "add 5a and subtract 6 from both sides of this equation to get:<BR>\n" );
document.write( "0 = a^2 + 5a - 6<BR>\n" );
document.write( "commute this equation to get:<BR>\n" );
document.write( "a^2 + 5a - 6 = 0<BR>\n" );
document.write( "factor this equation to get:<BR>\n" );
document.write( "(a+6) * (a-1) = 0<BR>\n" );
document.write( "solve for a to get:<BR>\n" );
document.write( "a = -6 or a = 1<BR>\n" );
document.write( "now substitute each of these values in your original equation to see if they are good solutions or are extraneous solutions.<BR>\n" );
document.write( "when you replace a with -6, your original equation becomes:<BR>\n" );
document.write( "sqrt(-5(-6)+6) = 6 which becomes:<BR>\n" );
document.write( "sqrt(30+6) = 6 which becomes:<BR>\n" );
document.write( "sqrt(36) = 6 which becomes:<BR>\n" );
document.write( "6 = 6 which is good, so the a = -6 is a good solution.<BR>\n" );
document.write( "when you replace a with 1, your original equation becomes:<BR>\n" );
document.write( "sqrt(-5(1)+6) = -1 which becomes:<BR>\n" );
document.write( "sqrt(-5+6) = -1 which becomes:<BR>\n" );
document.write( "sqrt(1) = -1 which is not a valid solution because sqrt(1) is equal to 1 and not -1.<BR>\n" );
document.write( "you can see this graphically by plotting both equations on the same graph and looking for the intersections.<BR>\n" );
document.write( "it is at the intersections that both equations have a common solution.<BR>\n" );
document.write( "you can see from the graph that there is an intersection when x = -6 but not an intersection when x = 1.\r<BR>\n" );
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document.write( "the solution is when x = -6 only.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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