document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=851445>Question 851445</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve the equation. check. <BR>\n" );
document.write( "logb 64 = 3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #512806 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=512806\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> logb(64) = 3 if and only if b^3 = 64 which means that b must be equal to 4 because 4^3 = 64\r<BR>\n" );
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document.write( "once you have the equation of b^3 = 64, you can take the log of both sides to get log10(b^3) = log10(64) which then becomes 3*log10(b) = log10(64) which then becomes log10(b) = log10(64)/3.\r<BR>\n" );
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document.write( "you can then use the log function of your calculator to get log10(b) = .6020599913.\r<BR>\n" );
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document.write( "this can only be true if 10^.6020599913 = b.\r<BR>\n" );
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document.write( "use your calculator again to get b = 4\r<BR>\n" );
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document.write( "  <BR>\n" );
document.write( " </SPAN>\n" );
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