document.write( "Question 851415: Solve. log7 100 - log7 (y+5) = log7 10 \n" ); document.write( "
Algebra.Com's Answer #512797 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
log7(100) - log7(y+5) = log7(10)
\n" ); document.write( "subtract log7(10) from both sides of the equation and add log(y+5) to both sides of the equation to get:
\n" ); document.write( "log7(100) - log7(10) = log7(y+5)
\n" ); document.write( "since log(a) - log(b) = log(a/b), your equation becomes:
\n" ); document.write( "log7(100/10) = log7(y+5)
\n" ); document.write( "simplify to get:
\n" ); document.write( "log7(10) = log7(y+5)
\n" ); document.write( "this means that 10 = y+5 which means that y = 5.
\n" ); document.write( "confirm by replacing y by 5 in the original equation to get:
\n" ); document.write( "log7(100) - log7(5+5) = log7(10)
\n" ); document.write( "simplify to get:
\n" ); document.write( "log7(100) - log7(10) = log7(10)
\n" ); document.write( "since log(a) - log(b) = log(a-b), your equation becomes:
\n" ); document.write( "log7(100/10) = log7(10)
\n" ); document.write( "simplify to get:
\n" ); document.write( "log7(10) = log7(10)
\n" ); document.write( "this confirms that the solution of y = 5 is good.\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );