document.write( "Question 851474: how many ounces of hamburger that is 75% lean must be mixed with hamburger that is 90% lean to get 65 ounces of hamburger that is 85% lean? \n" ); document.write( "
Algebra.Com's Answer #512768 by stanbon(75887)\"\" \"About 
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how many ounces of hamburger that is 75% lean must be mixed with hamburger that is 90% lean to get 65 ounces of hamburger that is 85% lean?
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\n" ); document.write( "Equation:
\n" ); document.write( "lean + lean = lean
\n" ); document.write( "0.75x + 0.90(65-x) = 0.85*65
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\n" ); document.write( "75x + 90*65 - 90x = 85*65
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\n" ); document.write( "-25x = -5*65
\n" ); document.write( "x = (1/5)65
\n" ); document.write( "x = 13 ounces (amt. of 75% hamburger needed)
\n" ); document.write( "-------
\n" ); document.write( "65-x = 52 ounces (amt. of 90% hamburger needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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