document.write( "Question 851474: how many ounces of hamburger that is 75% lean must be mixed with hamburger that is 90% lean to get 65 ounces of hamburger that is 85% lean? \n" ); document.write( "
Algebra.Com's Answer #512768 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! how many ounces of hamburger that is 75% lean must be mixed with hamburger that is 90% lean to get 65 ounces of hamburger that is 85% lean? \n" ); document.write( "-------- \n" ); document.write( "Equation: \n" ); document.write( "lean + lean = lean \n" ); document.write( "0.75x + 0.90(65-x) = 0.85*65 \n" ); document.write( "------------------------------ \n" ); document.write( "75x + 90*65 - 90x = 85*65 \n" ); document.write( "----------------------------- \n" ); document.write( "-25x = -5*65 \n" ); document.write( "x = (1/5)65 \n" ); document.write( "x = 13 ounces (amt. of 75% hamburger needed) \n" ); document.write( "------- \n" ); document.write( "65-x = 52 ounces (amt. of 90% hamburger needed) \n" ); document.write( "================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================== \n" ); document.write( " |