document.write( "Question 851457: An apple costs the same as two oranges. Together an orange and a banana costs 10 cents more than an apple. Two oranges cost 15 cents more than a banana. What's the cost for each fruit?\" \n" ); document.write( "
Algebra.Com's Answer #512757 by JulietG(1812)\"\" \"About 
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Here's what we know:
\n" ); document.write( "A = 2R
\n" ); document.write( "R + B = 10 + A
\n" ); document.write( "2R = B + 15
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\n" ); document.write( "Since A = 2R and 2R = B + 15, A = B + 15
\n" ); document.write( "Let's take that value of A and plug it into the second equation.
\n" ); document.write( "R + B = 10 + B + 15
\n" ); document.write( "R + B = B + 25
\n" ); document.write( "Subtract B from each side
\n" ); document.write( "R = 25
\n" ); document.write( ".
\n" ); document.write( "If oranges are .25, then apples are .50 each (An apple costs the same as two oranges.)
\n" ); document.write( "If 2 oranges cost .50 and a banana is .50 less than that, a banana is .35.
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\n" ); document.write( "Let's see if it works for the other equation: Together an orange and a banana costs 10 cents more than an apple.
\n" ); document.write( ".25 + .35 = .10 + .50
\n" ); document.write( ".60 = .60
\n" ); document.write( "Success!
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