document.write( "Question 851430: -sqrt(18)/sqrt(12)
\n" ); document.write( "The answer is -sqrt(6)/2\r
\n" ); document.write( "\n" ); document.write( "I am having beyond complications solving this problem. I have the answer, but I need help on how to actually solve it. Thanks!\r
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Algebra.Com's Answer #512753 by josh_jordan(263)\"\" \"About 
You can put this solution on YOUR website!
Hello. Here is how you would solve your problem.\r
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\n" ); document.write( "\n" ); document.write( "\"-sqrt%2818%29%2Fsqrt%2812%29\"\r
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\n" ); document.write( "\n" ); document.write( "First, simplify the radicals in the numerator and denominator:\r
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\n" ); document.write( "\n" ); document.write( "\"-sqrt%2818%29\" can be reduced to \"-3%2Asqrt%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%2812%29\" can be reduced to \"2%2Asqrt%283%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now, you are left with:\r
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\n" ); document.write( "\n" ); document.write( "\"%28-3%2Asqrt%282%29%29%2F%282%2Asqrt%283%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "You now have to rationalize the denominator, since you cannot have an irrational number, such as a root, in the denominator of a fraction. To do this, we can multiply both the numerator and denominator by \"sqrt%283%29\". This will eliminate the root from the denominator:\r
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\n" ); document.write( "\n" ); document.write( "\"%28-3%2Asqrt%282%29%2Asqrt%283%29%29%2F%282%2Asqrt%283%29%2Asqrt%283%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "This gives us:\r
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\n" ); document.write( "\n" ); document.write( "\"%28-3%2Asqrt%286%29%29%2F%282%2A3%29\" ----->\r
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\n" ); document.write( "\n" ); document.write( "\"%28-3%2Asqrt%286%29%29%2F6\"\r
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\n" ); document.write( "\n" ); document.write( "Finally, we can reduce the fraction down, since both the numerator and denominator of the fraction are divisible by 3. This gives us the final answer of:\r
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\n" ); document.write( "\n" ); document.write( "\"-sqrt%286%29%2F2\"
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