document.write( "Question 851368:
\n" );
document.write( "Carlos can travel 40 miles on his motorbike in the same time it takes Paul to travel 15 miles on his bike if Paul rides his bike at 20mi/hr slower then Carlos rides is motor bike find the speed for each bike \n" );
document.write( "
Algebra.Com's Answer #512729 by checkley79(3341) ![]() You can put this solution on YOUR website! C 40=RT OR T=40/R \n" ); document.write( "P 15=(R-20)T OR T=15/(R-20) \n" ); document.write( "40/R=15/(R-20) \n" ); document.write( "15R=40(R-20 \n" ); document.write( "15R=405-800 \n" ); document.write( "15R-40R=-800 \n" ); document.write( "-25R=-800 \n" ); document.write( "R=-800/-25 \n" ); document.write( "R=32 MPH FOR CARLOS' SPEED. \n" ); document.write( "32-20=12 MPH FOR PAUL. \n" ); document.write( "PROOF: \n" ); document.write( "40/32=15/12 \n" ); document.write( "1.25=1.25\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |