document.write( "Question 851246: 15 men take 21 days of 8 hrs. each to do a piece of work.How manydays of 6 hrs. each would it take
\n" ); document.write( "for 21 women if 3 women do as much work as 2 men?
\n" ); document.write( "(a) 30
\n" ); document.write( "(b) 20
\n" ); document.write( "(c) 19
\n" ); document.write( "(d) 29
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Algebra.Com's Answer #512654 by JulietG(1812)\"\" \"About 
You can put this solution on YOUR website!
21 days * 8 hours = 168. Multiply that by 15 men to get 2520 man-hours for this project.
\n" ); document.write( "The women in this equation work at the rate of 2/3 of the men. They'll need to have 2520 * 3/2 man-hours to equal the men. 2520*3/2= 3780 man-hours. Divide those hours among 21 women to get 3780/21 = 180. They're only working 6 hours. Divide 180 by 6 to get 180/6=30 days.
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