document.write( "Question 851008: Sketch the parabola \"+y=x%5E2%2Bx-6+\" by using its intercepts.
\n" ); document.write( "Please show all steps (and if you can explain where some of the numbers and stuff you get come from.)
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Algebra.Com's Answer #512604 by ankor@dixie-net.com(22740)\"\" \"About 
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Sketch the parabola y = x^2 + x - 6 by using its intercepts.
\n" ); document.write( "y intercept occurs when x = 0
\n" ); document.write( "y = 0^2 + 0 - 6
\n" ); document.write( "y = -6 is the y intercept
\n" ); document.write( ":
\n" ); document.write( "x intercepts occur when y = 0
\n" ); document.write( "x^2 + x - 6 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(x+3)(x-2) = 0
\n" ); document.write( "x = -3
\n" ); document.write( "x = +2
\n" ); document.write( "These are the x intercepts
\n" ); document.write( ":
\n" ); document.write( "You need a couple more coordinates to construct a graph
\n" ); document.write( "find y when x = -2 and x = +1
\n" ); document.write( "y = -2^2 - 2 - 6
\n" ); document.write( "7 = 4 - 1 - 6
\n" ); document.write( "y = -4
\n" ); document.write( ":
\n" ); document.write( "and x=+1
\n" ); document.write( "y = 1^2 + 1 - 6
\n" ); document.write( "y = -4
\n" ); document.write( ":
\n" ); document.write( "Plot the intercepts 0,-6; -3,0; 2,0; and points -2,-4; 1,-4
\n" ); document.write( "should look like this
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+x%5E2%2Bx-6%29+\"
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