document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=71685>Question 71685</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/06182939144/algebrahomeworkh>Algebra:Introductory and Intermediate</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> A butcher combines 100 lb of hamburger that costs $2.40 per pound with 60 lb of hamburger that costs $3.20 per pound. Find the cost of the hamburger mixture. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #51260 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=51260\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=cost of hamburger mixture\r<BR>\n" );
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document.write( "Now we know that the cost of the $2.40 mixture (100*2.40) plus the cost of the $3.20 mixture(60*3.20) must equal the cost of the final mixture (160x).  So our equation to solve is:\r<BR>\n" );
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document.write( "(100)($2.40)+(60)($3.20)=160x  get rid of parens\r<BR>\n" );
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document.write( "$240+$192=160x  collect like terms\r<BR>\n" );
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document.write( "$432=160x  divide both sides by 160<BR>\n" );
document.write( "x=$2.70 per pound-----------------------------cost of final mixture\r<BR>\n" );
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document.write( "CK\r<BR>\n" );
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document.write( "100(2.40)+60(3.20)=160(2.70)<BR>\n" );
document.write( "240+192=432<BR>\n" );
document.write( "432=432\r<BR>\n" );
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document.write( "Hope this helps----ptaylor<BR>\n" );
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