document.write( "Question 71686This question is from textbook Algebra: Introductory and Intermediate
\n" ); document.write( ": How many gallons of water must be mixed with 5 gal of a 20% sal solution to make a 16% salt solution? \n" ); document.write( "
Algebra.Com's Answer #51259 by ptaylor(2198)\"\" \"About 
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\n" ); document.write( "Lex x=Amount of water to be added\r
\n" ); document.write( "\n" ); document.write( "Now we know that the amount of pure salt in water (0) plus the amount of pure salt in the original 5 gal of the 20% solution (0.20*5) has to equal the amount of pure salt in the final mixture ((5+x)*0.16). So our equation to solve is:\r
\n" ); document.write( "\n" ); document.write( "(0.20)(5)=(5+x)(0.16)--get rid of the parens\r
\n" ); document.write( "\n" ); document.write( "1=0.8+0.16x subtract 0.8 from both sides
\n" ); document.write( "1-0.8=0.8-0.8+0.16x collect like terms
\n" ); document.write( "0.2=0.16x divide both sides by 0.16
\n" ); document.write( "x=1.25 gal---------------------------------amount of water needed\r
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "5+1.25=6.25
\n" ); document.write( "6.25(.16)=1
\n" ); document.write( "and 5(0.20)=1
\n" ); document.write( "1=1\r
\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor \n" ); document.write( "
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