document.write( "Question 851082: The hypotenuse of a right triangle is 75 inches long. One leg is 5 inch(es) longer than the other. Find the lengths of the legs of the triangle. Round your answers to the nearest tenth of an inch. \n" ); document.write( "

Algebra.Com's Answer #512585 by ramkikk66(644) $\"\"$ $\"About$

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document.write( "The hypotenuse of a right triangle is 75 inches long. One leg is 5 inch(es) longer than the other. Find the lengths of the legs of the triangle. Round your answers to the nearest tenth of an inch.\r\n" );
document.write( "Solution:\r\n" );
document.write( "Let the shortest side be x\r\n" );
document.write( "Then the second side is x + 5\r\n" );
document.write( "And the hypotenuse is 75 in. long.\r\n" );
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document.write( "Applying Pythagoras theorem,\r\n" );
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document.write( "i.e.  or Dividing it by 2 throughout\r\n" );
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document.write( "This can be solved using the quadratic solver as shown below.\r\n" );
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document.write( "Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation  (in our case ) has the following solutons:\r\n" );
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document.write( "  For these solutions to exist, the discriminant  should not be a negative number.\r\n" );
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document.write( "  First, we need to compute the discriminant : .\r\n" );
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document.write( "  Discriminant d=11225 is greater than zero. That means that there are two solutions: .\r\n" );
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document.write( "    Quadratic expression  can be factored:\r\n" );
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document.write( "  Again, the answer is: 50.4740502510427, -55.4740502510427.\n" );
document.write( "Here's your graph:\n" );
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document.write( "The solution is the positive value of x is 50.5 inches (rounded off), since the length of a side cannot be negative.\r\n" );
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document.write( "So the lengths of the sides are , , and  inches respectively.\r\n" );
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