document.write( "Question 850997: Solve the system by addition: \r
\n" ); document.write( "\n" ); document.write( "x-4y=-6
\n" ); document.write( "2x+y=15
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Algebra.Com's Answer #512576 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Multiply both sides of equation 2 by 4 to get\r
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\n" ); document.write( "\n" ); document.write( "x-4y=-6
\n" ); document.write( "2x+y=15\r
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\n" ); document.write( "\n" ); document.write( "x-4y=-6
\n" ); document.write( "4(2x+y)=4*15\r
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\n" ); document.write( "\n" ); document.write( "x-4y=-6
\n" ); document.write( "8x+4y=60\r
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\n" ); document.write( "\n" ); document.write( "Now add the equations\r
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\n" ); document.write( "\n" ); document.write( "x-4y=-6
\n" ); document.write( "8x+4y=60
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\n" ); document.write( "9x+0y=54\r
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\n" ); document.write( "\n" ); document.write( "So that means \"9x=54\" ----> \"x+=+54%2F9+=+6\"\r
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\n" ); document.write( "\n" ); document.write( "Now that we know that \"x+=+6\", we can use this to find y. \r
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\n" ); document.write( "\n" ); document.write( "Pick any equation with x and y in it, plug in \"x+=+6\" and solve for y. I'm going to use the first equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x-4y=-6\"\r
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\n" ); document.write( "\n" ); document.write( "\"6-4y=-6\"\r
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\n" ); document.write( "\n" ); document.write( "\"-4y=-6-6\"\r
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\n" ); document.write( "\n" ); document.write( "\"-4y=-12\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=-12%2F%28-4%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=3\"\r
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\n" ); document.write( "\n" ); document.write( "So, \"x+=+6\" and \"y=3\"
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