document.write( "Question 851056: The scores on the Wechsler Adult Intelligence Scale are approximately Normal with mean = 100 and standard deviation = 15\r
\n" ); document.write( "\n" ); document.write( "The proportion of adults with scores above 130 is closest to\r
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\n" ); document.write( "0.001\r
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\n" ); document.write( "0.025\r
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\n" ); document.write( "0.050\r
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\n" ); document.write( "0.950\r
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Algebra.Com's Answer #512554 by jim_thompson5910(35256)\"\" \"About 
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130-100 = 30\r
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\n" ); document.write( "\n" ); document.write( "30/15 = 2\r
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\n" ); document.write( "\n" ); document.write( "So 130 is 2 standard deviations above the mean. \r
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\n" ); document.write( "\n" ); document.write( "95% of the distribution is within 2 standard deviations of the mean (using the empirical rule).\r
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\n" ); document.write( "\n" ); document.write( "So 100 - 95 = 5% of the distribution is in the two tails. \r
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\n" ); document.write( "\n" ); document.write( "This means 5/2 = 2.5% of the population is in one tail\r
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\n" ); document.write( "\n" ); document.write( "So that's why the answer is 0.025 (since 2.5% = 0.025)
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