document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=851058>Question 851058</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If cos beta equals -5/13 and cot beta is more than 0, find the remaining trig values. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #512530 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=512530\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If cos beta equals -5/13 and cot beta is more than 0, find the remaining trig values.<BR>\n" );
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document.write( "cos = x/r<BR>\n" );
document.write( "Since cos = -5/13, x = -5 and r = 13<BR>\n" );
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document.write( "Since cos is negative and cot is positive, beta is in QIII where<BR>\n" );
document.write( "x is negative and y is negative.<BR>\n" );
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document.write( "y = -sqrt[13^2-5^2] = -12<BR>\n" );
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document.write( "sin = y/r = -12/13<BR>\n" );
document.write( "cos = x/r = -5/13<BR>\n" );
document.write( "tan = y/x = 12/5<BR>\n" );
document.write( "csc = r/y = -13/12<BR>\n" );
document.write( "sec = r/x = -13/5<BR>\n" );
document.write( "cot = x/y = 5/12<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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