document.write( "Question 71595: log base 4 x+log base 4 (x-3)=1 \n" ); document.write( "

Algebra.Com's Answer #51251 by stanbon(75887) $\"\"$ $\"About$

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log base 4 x+log base 4 (x-3)=1\r
\n" ); document.write( "\n" ); document.write( "log (base 4) x(x-3) = 1
\n" ); document.write( "x(x-3)=4
\n" ); document.write( "x^2-3x-4=0
\n" ); document.write( "(x-4)(x+1)=0
\n" ); document.write( "x=4 or x=-1
\n" ); document.write( "Only x=4 is an answer; x=-1 is extraneous
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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