document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=71591>Question 71591</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 0.3^1+x= 1.7^2x-1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #51250 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=51250\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 0.3^(1+x)= 1.7^(2x-1)\r<BR>\n" );
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document.write( "Take the log of both sides to get:\r<BR>\n" );
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document.write( "(1+x) log 0.3  = (2x-1) log 1.7\r<BR>\n" );
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document.write( "log0.3 + x(log0.3) = 2x(log1.7) -log1.7<BR>\n" );
document.write( "x(log0.3-2log1.7)= -(log0.3+log1.7)\r<BR>\n" );
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document.write( "x= -(log0.3+log1.7)/(log0.3-2log1.7)\r<BR>\n" );
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document.write( "x= 0.2924../-0.98378...<BR>\n" );
document.write( "x= -0.2972522699...<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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