document.write( "Question 850808: assume there is a 4 person family and you are looking at the gender of the children. let the random variable X stand for the number of females in the 4 children in the sample.
\n" ); document.write( "list the discrete random variable distribution in table format for this situation. find the mean,variance, and standard deviation for this distribution.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #512474 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Look at all possible outcomes, then count the number of females.
\n" ); document.write( "MMMM=0
\n" ); document.write( "MMMF=1
\n" ); document.write( "MMFM=1
\n" ); document.write( "MMFF=2
\n" ); document.write( "MFMM=1
\n" ); document.write( "MFMF=2
\n" ); document.write( "MFFM=2
\n" ); document.write( "MFFF=3
\n" ); document.write( "FMMM=1
\n" ); document.write( "FMMF=2
\n" ); document.write( "FMFM=2
\n" ); document.write( "FMFF=3
\n" ); document.write( "FFMM=2
\n" ); document.write( "FFMF=3
\n" ); document.write( "FFFM=3
\n" ); document.write( "FFFF=4
\n" ); document.write( "So then the discrete probability distribution looks like,
\n" ); document.write( "0,1/16
\n" ); document.write( "1,4/16
\n" ); document.write( "2,6/16
\n" ); document.write( "3,4/16
\n" ); document.write( "4,1/16
\n" ); document.write( "\"m=sum%28x%2Ap%28x%29%29=%280%2A1%2B1%2A4%2B2%2A6%2B3%2A4%2B4%2A1%29%2F16=32%2F16=2\"
\n" ); document.write( "
\n" ); document.write( "\"sigma=sqrt%28Var%29=1\"
\n" ); document.write( "
\n" );