document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=850791>Question 850791</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, i am doing a project for my school and need to draw 3 rectangles where the area is less than the perimeter. Can you help me? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #512444 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=512444\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if the length is 1 or 2, then you can make the width any value greater than or equal to 1 and the area will be less than the perimeter.\r<BR>\n" );
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document.write( "if the length is greater than 2, then there is a formula that can help you figure out what the width needs to be.\r<BR>\n" );
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document.write( "3 examples are:\r<BR>\n" );
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document.write( "length = 1 and width = 5<BR>\n" );
document.write( "length = 2 and width = 5<BR>\n" );
document.write( "length = 3 and width = 4\r<BR>\n" );
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document.write( "in the first case, area = 5 and perimeter = 12<BR>\n" );
document.write( "in the second case, area = 10 and perimeter = 14<BR>\n" );
document.write( "in the third case, area = 12 and perimeter = 14\r<BR>\n" );
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document.write( "area equals length times width.<BR>\n" );
document.write( "perimeter equals 2 times length plus 2 times width.\r<BR>\n" );
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document.write( "the formula for when length is greater than 2 is:\r<BR>\n" );
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document.write( "W < (2L) / (L-2)\r<BR>\n" );
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document.write( "for example:\r<BR>\n" );
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document.write( "when L is equal to 3, W must be smaller than 6.\r<BR>\n" );
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document.write( "in the example above, L was equal to 3 and W was equal to 4 which is smaller than 6 and the area was less than the perimeter.\r<BR>\n" );
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document.write( "if L was equal to 3 and W was equal to 7, then area would have been equal to 3*7 = 21 and perimeter would have been equal to 2*3 + 2*7 = 6 + 14 = 20.<BR>\n" );
document.write( "in that case the area of 21 would have been greater than the perimeter of 20.\r<BR>\n" );
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document.write( "  </SPAN>\n" );
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