document.write( "Question 850687: Bianca has $4000 invested, part at 5% per annum and the remainder at 3% per annum simple interest. the total income year from these investments is $168. how much has she invested at each rate. \n" ); document.write( "
Algebra.Com's Answer #512401 by harpazo(655)\"\" \"About 
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\n" ); document.write( "Let x = amount invested at 5%
\n" ); document.write( "Let (4000-x) = amount invested at 3%\r
\n" ); document.write( "\n" ); document.write( "Your equation is:\r
\n" ); document.write( "\n" ); document.write( "0.05x + 0.03(4000-x) = 168\r
\n" ); document.write( "\n" ); document.write( "Can you take it from here?
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