document.write( "Question 850740: Given that f(x)=ax^2+bx+5, f(3)=2 and f'(3)=2 find the values of a and b \n" ); document.write( "
Algebra.Com's Answer #512341 by Fombitz(32388)\"\" \"About 
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\"f%28x%29=ax%5E2%2Bbx%2B5\"
\n" ); document.write( "\"f%27%28x%29=2ax%2Bb\"
\n" ); document.write( ".
\n" ); document.write( ".\r
\n" ); document.write( "\n" ); document.write( "\"f%283%29=a%283%29%5E2%2Bb%283%29%2B5=9a%2B3b%2B5=2\"
\n" ); document.write( "\"9a%2B3b=-3\"
\n" ); document.write( "1.\"3a%2Bb=-1\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "\"f%27%283%29=2a%283%29%2Bb=2\"
\n" ); document.write( "2.\"6a%2Bb=2\"
\n" ); document.write( "From eq. 1,
\n" ); document.write( "\"b=-3a-1\"
\n" ); document.write( "Substitute into eq. 2,
\n" ); document.write( "\"6a-3a-1=2\"
\n" ); document.write( "\"3a=3\"
\n" ); document.write( "\"a=1\"
\n" ); document.write( "Then,
\n" ); document.write( "\"b=-3%281%29-1=-3-1=-4\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "\"f%28x%29=x%5E2-4x%2B5\"
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