document.write( "Question 850594: a.
\n" ); document.write( "The length of a picture frame is 3 inches more than its width. The perimeter of the frame is 34 inches. Find the length and width of the frame\r
\n" ); document.write( "\n" ); document.write( "b. The picture inside of the frame is surrounded by 1/2 inch of frame on all sides. What is the perimeter of the picture \n" ); document.write( "
Algebra.Com's Answer #512339 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
Width = x
\n" ); document.write( "Length = x + 3
\n" ); document.write( "Perimeter = 2*width + 2*length
\n" ); document.write( "34 = 2x + 2(x + 3)
\n" ); document.write( "34 = 2x + 2x + 6
\n" ); document.write( "34 = 4x + 6
\n" ); document.write( "4x = 34 - 6
\n" ); document.write( "4x = 28
\n" ); document.write( "x = 7
\n" ); document.write( "Width = 7 inches
\n" ); document.write( "Length = 10 inches
\n" ); document.write( "If the picture has 1/2 inch border all around it
\n" ); document.write( "This will equal 1 inch off length and width of frame
\n" ); document.write( "Width = 6 inches
\n" ); document.write( "Length = 9 inches.
\n" ); document.write( "Perimeter = 2*width + 2*length
\n" ); document.write( "Perimeter = 12 + 18
\n" ); document.write( "Perimeter = 30 inches
\n" ); document.write( "Hope this helps.
\n" ); document.write( ":-) \n" ); document.write( "
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