document.write( "Question 850682: Mary works 2.5 times faster than peter.together,they do a job in 12.5 hours.how long does it take mary working alone to do the same job? \n" ); document.write( "
Algebra.Com's Answer #512302 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Mary works 2.5 times faster than peter.together,they do a job in 12.5 hours.how long does it take mary working alone to do the same job? \n" ); document.write( "*** \n" ); document.write( "let x=time it takes peter to finish the job working alone \n" ); document.write( "1/x=his work rate \n" ); document.write( "2.5/x=mary's work rate \n" ); document.write( "1/12.5=work rate peter and mary working together to finish the job \n" ); document.write( ".. \n" ); document.write( "sum of indv. work rates=work rate working together \n" ); document.write( " \n" ); document.write( "3.5/x=1/12.5 \n" ); document.write( "x=43.75 \n" ); document.write( "hours it takes mary working alone to do the same job=43.75/2.5=17.5 \n" ); document.write( " \n" ); document.write( " |