document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=849782>Question 849782</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If an alloy is 20% zinc and 80% copper, how many grams of each will be required to make 750 grams of the alloy? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #512291 by </B><A HREF=/tutors/aboutme.mpl?userid=hamsanash1981@gmail.com><B>hamsanash1981@gmail.com(151)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=hamsanash1981@gmail.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=512291\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Total grams of alloy = 750 in which 80% of Copper is mixed then, required grams of copper in 750 grams = 750 *80/100 = 600 grams<BR>\n" );
document.write( "Required grams of zinc in 750 grams = 750 *20/100 = 150 grams<BR>\n" );
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