document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=850635>Question 850635</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the mean of six numbers is 41 three of the numbers are 32,31 and 42 the remaining three numbers each equal to a.   what is the sum of six numbers?. find the value?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #512275 by </B><A HREF=/tutors/aboutme.mpl?userid=hamsanash1981@gmail.com><B>hamsanash1981@gmail.com(151)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=hamsanash1981@gmail.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=512275\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Mean of six numbers is 41, then total sum = 41*6 = 246<BR>\n" );
document.write( "Given the numbers are 32,31,42 and other three are a,a,a<BR>\n" );
document.write( "then, 32+31+42+a+a+a = 246<BR>\n" );
document.write( "105+ 3a = 246<BR>\n" );
document.write( "3a = 141<BR>\n" );
document.write( "a = 47 </SPAN>\n" );
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