document.write( "Question 850615: how do I factor -5t^2+40t-35 completely?
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Algebra.Com's Answer #512261 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"-5t%5E2%2B40t-35\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"-5%28t%5E2-8t%2B7%29\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"-5%28t%5E2-t-7t%2B7%29\"$ See Special Note below\r
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\n" ); document.write( "\n" ); document.write( " $\"-5%28%28t%5E2-t%29%2B%28-7t%2B7%29%29\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"-5%28t%28t-1%29%2B%28-7t%2B7%29%29\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"-5%28t%28t-1%29-7%28t-1%29%29\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"-5%28t-7%29%28t-1%29\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"-5t%5E2%2B40t-35\"$ completely factors to $\"-5%28t-7%29%28t-1%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "Special Note: You need to find two numbers that multiply to 7 (last term in $\"t%5E2-8t%2B7\"$ ) and that also add to -8 (middle coefficient in $\"t%5E2-8t%2B7\"$ ). These two numbers are -1 and -7. So that's why $\"-8t\"$ breaks up into $\"-t-7t\"$ . From there, we factor by grouping. \n" ); document.write( "

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